Find the area $ A $ of a pyramid if slant height $s = 6.1$ and base area $B = 40.96$.

$A = 119.04$

STEP 1: find side $ a $

To find side $ a $ use formula:

After substituting $ B = 40.96 $ we have:

$$ B = a^2 $$ $$ a^2 = 40.96 $$ $$ a = \sqrt{ 40.96 } $$ $$ a = 6.4 $$

STEP 2: find lateral surface $ L $

To find lateral surface $ L $ use formula:

$$ L = 2 \cdot a \cdot s $$

After substituting $ a = 6.4 $ and $ s = 6.1 $ we have:

$$ L = 12.8 \cdot 6.1 $$$$ L = 78.08 $$

STEP 3: find total surface $ A $

To find total surface $ A $ use formula:

$$ A = B + L $$

After substituting $ B = 40.96 $ and $ L = 78.08 $ we have:

$$ A = 40.96 + 78.08 $$ $$ A = 40.96 + 78.08 $$ $$ A = 119.04 $$

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