Find the volume $ V $ of a pyramid if side $a = 25$ and slant height $s = 27$.

$V = \frac{ 625 \sqrt{ 2291}}{ 6 }$

STEP 1: find height $ h $

To find height $ h $ use Pythagorean Theorem:

$$ h^2 + \frac{ a^2 }{ 4 } = s^2 $$

After substituting $ a = 25 $ and $ s = 27 $ we have:

$$ h ^ {\,2} + \frac{ 25^2 }{ 4 } = 27^2 $$ $$ h ^ {\,2} + \frac{ 625 }{ 4 } = 27^2 $$ $$ h ^ {\,2} + \frac{ 625 }{ 4 } = 27^2 $$ $$ h ^ {\,2} = 729 - \frac{ 625 }{ 4 } $$ $$ h ^ {\,2} = \frac{ 2291 }{ 4 } $$ $$ h = \sqrt{ \frac{ 2291 }{ 4 } } $$$$ h = \frac{\sqrt{ 2291 }}{ 2 } $$

STEP 2: find volume $ V $

To find volume $ V $ use formula:

$$ V = \dfrac{ a ^{ 2 } \cdot h }{ 3 } $$

After substituting $ a = 25 $ and $ h = \frac{\sqrt{ 2291 }}{ 2 } $ we have:

$$ V = \dfrac{ 625 \cdot \frac{\sqrt{ 2291 }}{ 2 } }{ 3 }$$$$ V = \dfrac{ \frac{ 625 \sqrt{ 2291}}{ 2 } }{ 3 } $$$$ V = \frac{ 625 \sqrt{ 2291}}{ 6 } $$

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