Find the lateral edge $ e $ of a pyramid if side $a = 52.86$ and slant height $s = 42.79$.
Answer
$e = 50.2944$
Explanation
To find lateral edge $ e $ use Pythagorean Theorem:
$$ s^2 + \frac{ a^2 }{ 4 } = e^2 $$After substituting $ s = 42.79 $ and $ a = 52.86 $ we have:
$$ 42.79^2 + \frac{ 52.86^2 }{ 4 }= e^2 $$ $$ 1830.9841 + \frac{ 2794.1796 }{ 4 }= e^2 $$ $$ 1830.9841 + 698.5449 = e^2 $$ $$ e^2 = 2529.529 $$ $$ e = \sqrt{ 2529.529 } $$$$ e = 50.2944 $$This page was created using
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