Find the lateral edge $ e $ of a pyramid if side $a = 2$ and slant height $s = 1.619$.
Answer
$e = 1.9029$
Explanation
To find lateral edge $ e $ use Pythagorean Theorem:
$$ s^2 + \frac{ a^2 }{ 4 } = e^2 $$After substituting $ s = 1.619 $ and $ a = 2 $ we have:
$$ 1.619^2 + \frac{ 2^2 }{ 4 }= e^2 $$ $$ 2.6212 + \frac{ 4 }{ 4 }= e^2 $$ $$ 2.6212 + 1 = e^2 $$ $$ e^2 = 3.6212 $$ $$ e = \sqrt{ 3.6212 } $$$$ e = 1.9029 $$This page was created using
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