Find the lateral edge $ e $ of a pyramid if side $a = 10.5$ and slant height $s = 15.13$.
Answer
$e = 16.015$
Explanation
To find lateral edge $ e $ use Pythagorean Theorem:
$$ s^2 + \frac{ a^2 }{ 4 } = e^2 $$After substituting $ s = 15.13 $ and $ a = 10.5 $ we have:
$$ 15.13^2 + \frac{ 10.5^2 }{ 4 }= e^2 $$ $$ 228.9169 + \frac{ 110.25 }{ 4 }= e^2 $$ $$ 228.9169 + 27.5625 = e^2 $$ $$ e^2 = 256.4794 $$ $$ e = \sqrt{ 256.4794 } $$$$ e = 16.015 $$This page was created using
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