Find the lateral edge $ e $ of a pyramid if side $a = 0.56$ and slant height $s = 0.453$.
Answer
$e = 0.5325$
Explanation
To find lateral edge $ e $ use Pythagorean Theorem:
$$ s^2 + \frac{ a^2 }{ 4 } = e^2 $$After substituting $ s = 0.453 $ and $ a = 0.56 $ we have:
$$ 0.453^2 + \frac{ 0.56^2 }{ 4 }= e^2 $$ $$ 0.2052 + \frac{ 0.3136 }{ 4 }= e^2 $$ $$ 0.2052 + 0.0784 = e^2 $$ $$ e^2 = 0.2836 $$ $$ e = \sqrt{ 0.2836 } $$$$ e = 0.5325 $$This page was created using
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