Find the slant height $ s $ of a pyramid if side $a = 12$ and height $h = 10$.
Answer
$s = 2 \sqrt{ 34 }$
Explanation
To find slant height $ s $ use Pythagorean Theorem:
$$ h^2 + \frac{ a^2 }{ 4 } = s^2 $$After substituting $ h = 10 $ and $ a = 12 $ we have:
$$ 10^2 + \frac{ 12^2 }{ 4 }= s^2 $$ $$ 100 + \frac{ 144 }{ 4 }= s^2 $$ $$ 100 + 36 = s^2 $$ $$ s^2 = 136 $$ $$ s = \sqrt{ 136 } $$$$ s = 2 \sqrt{ 34 } $$This page was created using
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