Find the height $ h $ of a pyramid if side $a = 3$ and slant height $s = 3$.
Answer
$h = \frac{ 3 \sqrt{ 3}}{ 2 }$
Explanation
To find height $ h $ use Pythagorean Theorem:
$$ h^2 + \frac{ a^2 }{ 4 } = s^2 $$After substituting $ a = 3 $ and $ s = 3 $ we have:
$$ h ^ {\,2} + \frac{ 3^2 }{ 4 } = 3^2 $$ $$ h ^ {\,2} + \frac{ 9 }{ 4 } = 3^2 $$ $$ h ^ {\,2} + \frac{ 9 }{ 4 } = 3^2 $$ $$ h ^ {\,2} = 9 - \frac{ 9 }{ 4 } $$ $$ h ^ {\,2} = \frac{ 27 }{ 4 } $$ $$ h = \sqrt{ \frac{ 27 }{ 4 } } $$$$ h = \frac{ 3 \sqrt{ 3}}{ 2 } $$This page was created using
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