Find the lateral area $ L $ of a pyramid if slant height $s = 6.1$ and base area $B = 40.96$.
Answer
$L = 78.08$
Explanation
STEP 1: find side $ a $
To find side $ a $ use formula:
After substituting $ B = 40.96 $ we have:
$$ B = a^2 $$ $$ a^2 = 40.96 $$ $$ a = \sqrt{ 40.96 } $$ $$ a = 6.4 $$STEP 2: find lateral surface $ L $
To find lateral surface $ L $ use formula:
$$ L = 2 \cdot a \cdot s $$After substituting $ a = 6.4 $ and $ s = 6.1 $ we have:
$$ L = 12.8 \cdot 6.1 $$$$ L = 78.08 $$This page was created using
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