Find the lateral area $ L $ of a pyramid if slant height $s = 14$ and base area $B = 6$.
Answer
$L = 28 \sqrt{ 6 }$
Explanation
STEP 1: find side $ a $
To find side $ a $ use formula:
After substituting $ B = 6 $ we have:
$$ B = a^2 $$ $$ a^2 = 6 $$ $$ a = \sqrt{ 6 } $$STEP 2: find lateral surface $ L $
To find lateral surface $ L $ use formula:
$$ L = 2 \cdot a \cdot s $$After substituting $ a = \sqrt{ 6 } $ and $ s = 14 $ we have:
$$ L = 2 \sqrt{ 6 } \cdot 14 $$$$ L = 28 \sqrt{ 6 } $$This page was created using
Pyramid Calculator