Find the side $ a $ of a pyramid if height $h = 72$ and slant height $s = 97$.
Answer
$a = 130$
Explanation
To find side $ a $ use Pythagorean Theorem:
$$ h^2 + \frac{ a^2 }{ 4 } = s^2 $$After substituting $ h = 72 $ and $ s = 97 $ we have:
$$ 72^2 + \frac{ a^2 }{ 4 } = 97^2 $$ $$ \frac{ a^2 }{ 4 } = 97^2 - 72^2 $$ $$ \frac{ a^2 }{ 4 } = 9409 - 5184 $$ $$ a^2 = 4225 \cdot 4 $$ $$ a^2 = 16900 $$ $$ a = \sqrt{ 16900 } $$$$ a = 130 $$This page was created using
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