Find the prime factorization of number 9800.
Answer
The prime factorization of 9800 is:
$$ 9800 = 2\cdot2\cdot2\cdot5\cdot5\cdot7\cdot7 $$Which is the same as :
$$ 9800 = 2^{3}\cdot5^{2}\cdot7^{2} $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 9800 can be written as 10 × 980. |
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| 10 can be written as 2 × 5. |
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| 980 can be written as 10 × 98. |
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| 10 can be written as 2 × 5. |
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| 98 can be written as 2 × 49. |
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| 49 can be written as 7 × 7. |
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| The end nodes are the prime factors of the number 9800. |
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