Find the prime factorization of number 6120.
Answer
The prime factorization of 6120 is:
$$ 6120 = 2\cdot2\cdot2\cdot3\cdot3\cdot5\cdot17 $$Which is the same as :
$$ 6120 = 2^{3}\cdot3^{2}\cdot5\cdot17 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 6120 can be written as 10 × 612. |
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| 10 can be written as 2 × 5. |
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| 612 can be written as 2 × 306. |
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| 306 can be written as 2 × 153. |
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| 153 can be written as 3 × 51. |
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| 51 can be written as 3 × 17. |
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| The end nodes are the prime factors of the number 6120. |
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