Find the prime factorization of number 2800.
Answer
The prime factorization of 2800 is:
$$ 2800 = 2\cdot2\cdot2\cdot2\cdot5\cdot5\cdot7 $$Which is the same as :
$$ 2800 = 2^{4}\cdot5^{2}\cdot7 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 2800 can be written as 10 × 280. |
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| 10 can be written as 2 × 5. |
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| 280 can be written as 10 × 28. |
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| 10 can be written as 2 × 5. |
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| 28 can be written as 2 × 14. |
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| 14 can be written as 2 × 7. |
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| The end nodes are the prime factors of the number 2800. |
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