Find the prime factorization of number 19800.
Answer
The prime factorization of 19800 is:
$$ 19800 = 2\cdot2\cdot2\cdot3\cdot3\cdot5\cdot5\cdot11 $$Which is the same as :
$$ 19800 = 2^{3}\cdot3^{2}\cdot5^{2}\cdot11 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 19800 can be written as 10 × 1980. |
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| 10 can be written as 2 × 5. |
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| 1980 can be written as 10 × 198. |
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| 10 can be written as 2 × 5. |
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| 198 can be written as 2 × 99. |
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| 99 can be written as 3 × 33. |
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| 33 can be written as 3 × 11. |
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| The end nodes are the prime factors of the number 19800. |
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