Find the prime factorization of number 12902400.
Answer
The prime factorization of 12902400 is:
$$ 12902400 = 2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot3\cdot3\cdot5\cdot5\cdot7 $$Which is the same as :
$$ 12902400 = 2^{13}\cdot3^{2}\cdot5^{2}\cdot7 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 12902400 can be written as 10 × 1290240. |
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| 10 can be written as 2 × 5. |
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| 1290240 can be written as 10 × 129024. |
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| 10 can be written as 2 × 5. |
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| 129024 can be written as 2 × 64512. |
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| 64512 can be written as 2 × 32256. |
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| 32256 can be written as 2 × 16128. |
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| 16128 can be written as 2 × 8064. |
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| 8064 can be written as 2 × 4032. |
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| 4032 can be written as 2 × 2016. |
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| 2016 can be written as 2 × 1008. |
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| 1008 can be written as 2 × 504. |
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| 504 can be written as 2 × 252. |
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| 252 can be written as 2 × 126. |
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| 126 can be written as 2 × 63. |
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| 63 can be written as 3 × 21. |
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| 21 can be written as 3 × 7. |
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| The end nodes are the prime factors of the number 12902400. |
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