Multiply polynomial $2 x + 10 x + 26$ by $2 x - 19 x + 18$ .

Answer

$(2 x + 10 x + 26) \cdot (2 x - 19 x + 18) = - 204 x^{2} - 226 x + 468$

Explanation

Step 1: First we have to write polynomials in descending order.

P (x) Q (x) = 12 x + 26 = - 17 x + 18

In this example we are multiplying two binomials so FOIL method can be used.

(12 x + 26) \cdot (- 17 x + 18) = FIRST 12 x \cdot (- 17 x) + OUTER 12 x \cdot 18 + INNER 26 \cdot (- 17 x) + LAST 26 \cdot 18 = = - 204 x^{2} + 216 x + (- 442 x) + 468 = = - 204 x^{2} + 216 x + (- 442 x) + 468 = = - 204 x^{2} - 226 x + 468;

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Multiply polynomial 2x+10x+26 by 2x−19x+18.

(2x+10x+26)⋅(2x−19x+18)=−204x2−226x+468

Multiply polynomial $2 x + 10 x + 26$ by $2 x - 19 x + 18$ .

$(2 x + 10 x + 26) \cdot (2 x - 19 x + 18) = - 204 x^{2} - 226 x + 468$