Multiply polynomial $2 x - x - 6$ by $2 x - 4 x + 3$ .

Answer

$(2 x - x - 6) \cdot (2 x - 4 x + 3) = - 2 x^{2} + 15 x - 18$

Explanation

Step 1: First we have to write polynomials in descending order.

P (x) Q (x) = x - 6 = - 2 x + 3

In this example we are multiplying two binomials so FOIL method can be used.

(x - 6) \cdot (- 2 x + 3) = FIRST x \cdot (- 2 x) + OUTER x \cdot 3 + INNER (- 6) \cdot (- 2 x) + LAST (- 6) \cdot 3 = = - 2 x^{2} + 3 x + 12 x + (- 18) = = - 2 x^{2} + 3 x + 12 x + (- 18) = = - 2 x^{2} + 15 x - 18;

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Multiply polynomial 2x−x−6 by 2x−4x+3.

(2x−x−6)⋅(2x−4x+3)=−2x2+15x−18

Multiply polynomial $2 x - x - 6$ by $2 x - 4 x + 3$ .

$(2 x - x - 6) \cdot (2 x - 4 x + 3) = - 2 x^{2} + 15 x - 18$