Multiply polynomial $2 x - 19 x + 18$ by $2 x + 10 x + 26$ .

Answer

$(2 x - 19 x + 18) \cdot (2 x + 10 x + 26) = - 204 x^{2} - 226 x + 468$

Explanation

Step 1: First we have to write polynomials in descending order.

P (x) Q (x) = - 17 x + 18 = 12 x + 26

In this example we are multiplying two binomials so FOIL method can be used.

(- 17 x + 18) \cdot (12 x + 26) = FIRST (- 17 x) \cdot 12 x + OUTER (- 17 x) \cdot 26 + INNER 18 \cdot 12 x + LAST 18 \cdot 26 = = - 204 x^{2} + (- 442 x) + 216 x + 468 = = - 204 x^{2} + (- 442 x) + 216 x + 468 = = - 204 x^{2} - 226 x + 468;

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Multiply polynomial 2x−19x+18 by 2x+10x+26.

(2x−19x+18)⋅(2x+10x+26)=−204x2−226x+468

Multiply polynomial $2 x - 19 x + 18$ by $2 x + 10 x + 26$ .

$(2 x - 19 x + 18) \cdot (2 x + 10 x + 26) = - 204 x^{2} - 226 x + 468$