Multiply polynomial $ \, \color{blue}{ x-5 } \, $ by $ \, \color{orangered}{ 2x-5 }$.

$$ \left( \color{blue}{x-5} \right) \cdot \left( \color{orangered}{2x-5} \right) = 2x^2-15x+25 $$

In this example we are multiplying two binomials so FOIL method can be used.

$$ \begin{aligned} \left( \color{blue}{ x-5}\right) \cdot \left( \color{orangered}{ 2x-5}\right) &= \underbrace{ \color{blue}{x} \cdot \color{orangered}{2x} }_{\text{FIRST}} + \underbrace{ \color{blue}{x} \cdot \left( \color{orangered}{-5} \right) }_{\text{OUTER}} + \underbrace{ \left( \color{blue}{-5} \right) \cdot \color{orangered}{2x} }_{\text{INNER}} + \underbrace{ \left( \color{blue}{-5} \right) \cdot \left( \color{orangered}{-5} \right) }_{\text{LAST}} = \\ &= 2x^2 + \left( -5x\right) + \left( -10x\right) + 25 = \\ &= 2x^2 + \left( -5x\right) + \left( -10x\right) + 25 = \\ &= 2x^2-15x+25; \end{aligned} $$

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