Multiply polynomial $4 x + 9 x - 78 x - 83 x - 42$ by $2 x + 5$ .

Answer

$(4 x + 9 x - 78 x - 83 x - 42) \cdot (2 x + 5) = - 296 x^{2} - 824 x - 210$

Explanation

Step 1: First we have to write polynomials in descending order.

P (x) Q (x) = - 148 x - 42 = 2 x + 5

In this example we are multiplying two binomials so FOIL method can be used.

(- 148 x - 42) \cdot (2 x + 5) = FIRST (- 148 x) \cdot 2 x + OUTER (- 148 x) \cdot 5 + INNER (- 42) \cdot 2 x + LAST (- 42) \cdot 5 = = - 296 x^{2} + (- 740 x) + (- 84 x) + (- 210) = = - 296 x^{2} + (- 740 x) + (- 84 x) + (- 210) = = - 296 x^{2} - 824 x - 210;

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Multiply polynomial 4x+9x−78x−83x−42 by 2x+5.

(4x+9x−78x−83x−42)⋅(2x+5)=−296x2−824x−210

Multiply polynomial $4 x + 9 x - 78 x - 83 x - 42$ by $2 x + 5$ .

$(4 x + 9 x - 78 x - 83 x - 42) \cdot (2 x + 5) = - 296 x^{2} - 824 x - 210$