Multiply polynomial $3 x + 5 x^{2}$ by $2 x - 1$ .

Answer

$(3 x + 5 x^{2}) \cdot (2 x - 1) = 10 x^{3} + x^{2} - 3 x$

Explanation

Step 1: First we have to write polynomials in descending order.

P (x) Q (x) = 5 x^{2} + 3 x = 2 x - 1

In this example we are multiplying two binomials so FOIL method can be used.

(5 x^{2} + 3 x) \cdot (2 x - 1) = FIRST 5 x^{2} \cdot 2 x + OUTER 5 x^{2} \cdot (- 1) + INNER 3 x \cdot 2 x + LAST 3 x \cdot (- 1) = = 10 x^{3} + (- 5 x^{2}) + 6 x^{2} + (- 3 x) = = 10 x^{3} + (- 5 x^{2}) + 6 x^{2} + (- 3 x) = = 10 x^{3} + x^{2} - 3 x;

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Multiply polynomial 3x+5x2 by 2x−1.

(3x+5x2)⋅(2x−1)=10x3+x2−3x

Multiply polynomial $3 x + 5 x^{2}$ by $2 x - 1$ .

$(3 x + 5 x^{2}) \cdot (2 x - 1) = 10 x^{3} + x^{2} - 3 x$