Multiply polynomial $ \, \color{blue}{ 3x-2 } \, $ by $ \, \color{orangered}{ 3x+4 }$.

$$ \left( \color{blue}{3x-2} \right) \cdot \left( \color{orangered}{3x+4} \right) = 9x^2+6x-8 $$

In this example we are multiplying two binomials so FOIL method can be used.

$$ \begin{aligned} \left( \color{blue}{ 3x-2}\right) \cdot \left( \color{orangered}{ 3x+4}\right) &= \underbrace{ \color{blue}{3x} \cdot \color{orangered}{3x} }_{\text{FIRST}} + \underbrace{ \color{blue}{3x} \cdot \color{orangered}{4} }_{\text{OUTER}} + \underbrace{ \left( \color{blue}{-2} \right) \cdot \color{orangered}{3x} }_{\text{INNER}} + \underbrace{ \left( \color{blue}{-2} \right) \cdot \color{orangered}{4} }_{\text{LAST}} = \\ &= 9x^2 + 12x + \left( -6x\right) + \left( -8\right) = \\ &= 9x^2 + 12x + \left( -6x\right) + \left( -8\right) = \\ &= 9x^2+6x-8; \end{aligned} $$

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