Multiply polynomial $- 3 + 30 x - 10 x$ by $2 x + 5$ .

Answer

$(- 3 + 30 x - 10 x) \cdot (2 x + 5) = 40 x^{2} + 94 x - 15$

Explanation

Step 1: First we have to write polynomials in descending order.

P (x) Q (x) = 20 x - 3 = 2 x + 5

In this example we are multiplying two binomials so FOIL method can be used.

(20 x - 3) \cdot (2 x + 5) = FIRST 20 x \cdot 2 x + OUTER 20 x \cdot 5 + INNER (- 3) \cdot 2 x + LAST (- 3) \cdot 5 = = 40 x^{2} + 100 x + (- 6 x) + (- 15) = = 40 x^{2} + 100 x + (- 6 x) + (- 15) = = 40 x^{2} + 94 x - 15;

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Multiply polynomial −3+30x−10x by 2x+5.

(−3+30x−10x)⋅(2x+5)=40x2+94x−15

Multiply polynomial $- 3 + 30 x - 10 x$ by $2 x + 5$ .

$(- 3 + 30 x - 10 x) \cdot (2 x + 5) = 40 x^{2} + 94 x - 15$