Multiply polynomial $- 2 + 2 x$ by $- 6 + 4 x$ .

Answer

$(- 2 + 2 x) \cdot (- 6 + 4 x) = 8 x^{2} - 20 x + 12$

Explanation

Step 1: First we have to write polynomials in descending order.

P (x) Q (x) = 2 x - 2 = 4 x - 6

In this example we are multiplying two binomials so FOIL method can be used.

(2 x - 2) \cdot (4 x - 6) = FIRST 2 x \cdot 4 x + OUTER 2 x \cdot (- 6) + INNER (- 2) \cdot 4 x + LAST (- 2) \cdot (- 6) = = 8 x^{2} + (- 12 x) + (- 8 x) + 12 = = 8 x^{2} + (- 12 x) + (- 8 x) + 12 = = 8 x^{2} - 20 x + 12;

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Multiply polynomial −2+2x by −6+4x.

(−2+2x)⋅(−6+4x)=8x2−20x+12

Multiply polynomial $- 2 + 2 x$ by $- 6 + 4 x$ .

$(- 2 + 2 x) \cdot (- 6 + 4 x) = 8 x^{2} - 20 x + 12$