Multiply polynomial $ \, \color{blue}{ 4r^2-4r-8 } \, $ by $ \, \color{orangered}{ 9r^3-5r^2-9r+7 }$.
Answer
$$ \left( \color{blue}{4r^2-4r-8} \right) \cdot \left( \color{orangered}{9r^3-5r^2-9r+7} \right) = 36r^5-56r^4-88r^3+104r^2+44r-56 $$
Explanation
Explanation is too long to display.
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