Multiply polynomial $ \, \color{blue}{ 4q-4 } \, $ by $ \, \color{orangered}{ 4q+4 }$.

$$ \left( \color{blue}{4q-4} \right) \cdot \left( \color{orangered}{4q+4} \right) = 16q^2-16 $$

In this example we are multiplying two binomials so FOIL method can be used.

$$ \begin{aligned} \left( \color{blue}{ 4q-4}\right) \cdot \left( \color{orangered}{ 4q+4}\right) &= \underbrace{ \color{blue}{4q} \cdot \color{orangered}{4q} }_{\text{FIRST}} + \underbrace{ \color{blue}{4q} \cdot \color{orangered}{4} }_{\text{OUTER}} + \underbrace{ \left( \color{blue}{-4} \right) \cdot \color{orangered}{4q} }_{\text{INNER}} + \underbrace{ \left( \color{blue}{-4} \right) \cdot \color{orangered}{4} }_{\text{LAST}} = \\ &= 16q^2 + 16q + \left( -16q\right) + \left( -16\right) = \\ &= 16q^2 + 16q + \left( -16q\right) + \left( -16\right) = \\ &= 16q^2-16; \end{aligned} $$

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