Multiply polynomial $ \, \color{blue}{ 2x+8 } \, $ by $ \, \color{orangered}{ 5x-13 }$.

$$ \left( \color{blue}{2x+8} \right) \cdot \left( \color{orangered}{5x-13} \right) = 10x^2+14x-104 $$

In this example we are multiplying two binomials so FOIL method can be used.

$$ \begin{aligned} \left( \color{blue}{ 2x+8}\right) \cdot \left( \color{orangered}{ 5x-13}\right) &= \underbrace{ \color{blue}{2x} \cdot \color{orangered}{5x} }_{\text{FIRST}} + \underbrace{ \color{blue}{2x} \cdot \left( \color{orangered}{-13} \right) }_{\text{OUTER}} + \underbrace{ \color{blue}{8} \cdot \color{orangered}{5x} }_{\text{INNER}} + \underbrace{ \color{blue}{8} \cdot \left( \color{orangered}{-13} \right) }_{\text{LAST}} = \\ &= 10x^2 + \left( -26x\right) + 40x + \left( -104\right) = \\ &= 10x^2 + \left( -26x\right) + 40x + \left( -104\right) = \\ &= 10x^2+14x-104; \end{aligned} $$

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