In this example we are multiplying two binomials so FOIL method can be used.
$$ \begin{aligned} \left( \color{blue}{ 2r-3}\right) \cdot \left( \color{orangered}{ 4r+4}\right) &= \underbrace{ \color{blue}{2r} \cdot \color{orangered}{4r} }_{\text{FIRST}} + \underbrace{ \color{blue}{2r} \cdot \color{orangered}{4} }_{\text{OUTER}} + \underbrace{ \left( \color{blue}{-3} \right) \cdot \color{orangered}{4r} }_{\text{INNER}} + \underbrace{ \left( \color{blue}{-3} \right) \cdot \color{orangered}{4} }_{\text{LAST}} = \\ &= 8r^2 + 8r + \left( -12r\right) + \left( -12\right) = \\ &= 8r^2 + 8r + \left( -12r\right) + \left( -12\right) = \\ &= 8r^2-4r-12; \end{aligned} $$