Multiply polynomial $- 6 + 7 i$ by $4 + 2 i$ .

Answer

$(- 6 + 7 i) \cdot (4 + 2 i) = 14 i^{2} + 16 i - 24$

Explanation

Step 1: First we have to write polynomials in descending order.

P (x) Q (x) = 7 i - 6 = 2 i + 4

In this example we are multiplying two binomials so FOIL method can be used.

(7 i - 6) \cdot (2 i + 4) = FIRST 7 i \cdot 2 i + OUTER 7 i \cdot 4 + INNER (- 6) \cdot 2 i + LAST (- 6) \cdot 4 = = 14 i^{2} + 28 i + (- 12 i) + (- 24) = = 14 i^{2} + 28 i + (- 12 i) + (- 24) = = 14 i^{2} + 16 i - 24;

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Multiply polynomial −6+7i by 4+2i.

(−6+7i)⋅(4+2i)=14i2+16i−24

Multiply polynomial $- 6 + 7 i$ by $4 + 2 i$ .

$(- 6 + 7 i) \cdot (4 + 2 i) = 14 i^{2} + 16 i - 24$