Multiply polynomial $- 4 + 3 r$ by $7 r - 2$ .

Answer

$(- 4 + 3 r) \cdot (7 r - 2) = 21 r^{2} - 34 r + 8$

Explanation

Step 1: First we have to write polynomials in descending order.

P (x) Q (x) = 3 r - 4 = 7 r - 2

In this example we are multiplying two binomials so FOIL method can be used.

(3 r - 4) \cdot (7 r - 2) = FIRST 3 r \cdot 7 r + OUTER 3 r \cdot (- 2) + INNER (- 4) \cdot 7 r + LAST (- 4) \cdot (- 2) = = 21 r^{2} + (- 6 r) + (- 28 r) + 8 = = 21 r^{2} + (- 6 r) + (- 28 r) + 8 = = 21 r^{2} - 34 r + 8;

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Multiply polynomial −4+3r by 7r−2.

(−4+3r)⋅(7r−2)=21r2−34r+8

Multiply polynomial $- 4 + 3 r$ by $7 r - 2$ .

$(- 4 + 3 r) \cdot (7 r - 2) = 21 r^{2} - 34 r + 8$