Combine like terms:

$$ \color{blue}{x} -2 \color{blue}{-12x} = \color{blue}{-11x} -2 $$

Add $-11x-2$ and $ \dfrac{20}{x} $ to get $ \dfrac{ \color{purple}{ -11x^2-2x+20 } }{ x }$.

Step 1: Write $ -11x-2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator.

Step 2: To add raitonal expressions, both fractions must have the same denominator.
We can create a common denominator by multiplying the first fraction by $\color{blue}{ x }$.

$$ \begin{aligned} -11x-2+ \frac{20}{x} & \xlongequal{\text{Step 1}} \frac{-11x-2}{\color{red}{1}} + \frac{20}{x} = \frac{ \left( -11x-2 \right) \cdot \color{blue}{ x }}{ 1 \cdot \color{blue}{ x }} + \frac{ 20 }{ x } = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ \color{purple}{ -11x^2-2x } }{ x } + \frac{ \color{purple}{ 20 } }{ x }=\frac{ \color{purple}{ -11x^2-2x+20 } }{ x } \end{aligned} $$

Subtract $2$ from $ \dfrac{-11x^2-2x+20}{x} $ to get $ \dfrac{ \color{purple}{ -11x^2-4x+20 } }{ x }$.

Step 1: Write $ 2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator.

Step 2: To subtract raitonal expressions, both fractions must have the same denominator.
We can create a common denominator by multiplying the second fraction by $\color{blue}{x}$.

$$ \begin{aligned} \frac{-11x^2-2x+20}{x} -2 & \xlongequal{\text{Step 1}} \frac{-11x^2-2x+20}{x} - \frac{2}{\color{red}{1}} = \frac{ -11x^2-2x+20 }{ x } - \frac{ 2 \cdot \color{blue}{ x }}{ 1 \cdot \color{blue}{ x }} = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ \color{purple}{ -11x^2-2x+20 } }{ x } - \frac{ \color{purple}{ 2x } }{ x }=\frac{ \color{purple}{ -11x^2-4x+20 } }{ x } \end{aligned} $$