Answer
$$x^2y+x^3-xy^2+3-x^3-xy^2+xy+6=x^2y-2xy^2+xy+9$$
Explanation
| $$ \begin{aligned}x^2y+x^3-xy^2+3-x^3-xy^2+xy+6& \xlongequal{ }x^2y+ \cancel{x^3}-xy^2+3 -\cancel{x^3}-xy^2+xy+6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2y-2xy^2+xy+9\end{aligned} $$ | |
| ① | Combine like terms: $$ x^2y+ \, \color{blue}{ \cancel{x^3}} \, \color{green}{-xy^2} + \color{orange}{3} \, \color{blue}{ -\cancel{x^3}} \, \color{green}{-xy^2} +xy+ \color{orange}{6} = x^2y \color{green}{-2xy^2} +xy+ \color{orange}{9} $$ |
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