Tap the blue circles to see an explanation.
$$ \begin{aligned}x(x+4)+3(x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2+4x+3x-6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2+7x-6\end{aligned} $$ | |
① | Multiply $ \color{blue}{x} $ by $ \left( x+4\right) $ $$ \color{blue}{x} \cdot \left( x+4\right) = x^2+4x $$Multiply $ \color{blue}{3} $ by $ \left( x-2\right) $ $$ \color{blue}{3} \cdot \left( x-2\right) = 3x-6 $$ |
② | Combine like terms: $$ x^2+ \color{blue}{4x} + \color{blue}{3x} -6 = x^2+ \color{blue}{7x} -6 $$ |