Find $ \left(x-2\right)^2 $ using formula.

$$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$

where $ A = \color{blue}{ x } $ and $ B = \color{red}{ 2 }$.

$$ \begin{aligned}\left(x-2\right)^2 = \color{blue}{x^2} -2 \cdot x \cdot 2 + \color{red}{2^2} = x^2-4x+4\end{aligned} $$

Multiply $ \color{blue}{x} $ by $ \left( x-1\right) $ $$ \color{blue}{x} \cdot \left( x-1\right) = x^2-x $$

Multiply each term of $ \left( \color{blue}{x^2-x}\right) $ by each term in $ \left( x^2-4x+4\right) $.

$$ \left( \color{blue}{x^2-x}\right) \cdot \left( x^2-4x+4\right) = x^4-4x^3+4x^2-x^3+4x^2-4x $$

Combine like terms:

$$ x^4 \color{blue}{-4x^3} + \color{red}{4x^2} \color{blue}{-x^3} + \color{red}{4x^2} -4x = x^4 \color{blue}{-5x^3} + \color{red}{8x^2} -4x $$

Multiply each term of $ \left( \color{blue}{x^4-5x^3+8x^2-4x}\right) $ by each term in $ \left( x^2-7x+13\right) $.

$$ \left( \color{blue}{x^4-5x^3+8x^2-4x}\right) \cdot \left( x^2-7x+13\right) = \\ = x^6-7x^5+13x^4-5x^5+35x^4-65x^3+8x^4-56x^3+104x^2-4x^3+28x^2-52x $$

Combine like terms:

$$ x^6 \color{blue}{-7x^5} + \color{red}{13x^4} \color{blue}{-5x^5} + \color{green}{35x^4} \color{orange}{-65x^3} + \color{green}{8x^4} \color{blue}{-56x^3} + \color{red}{104x^2} \color{blue}{-4x^3} + \color{red}{28x^2} -52x = \\ = x^6 \color{blue}{-12x^5} + \color{green}{56x^4} \color{blue}{-125x^3} + \color{red}{132x^2} -52x $$