$$ \begin{aligned}log\cdot2(x^2+1)-log\cdot2\cdot2^x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2glox^2+2glo-log\cdot2\cdot2^x\end{aligned} $$ | |
① | Multiply $ \color{blue}{2glo} $ by $ \left( x^2+1\right) $ $$ \color{blue}{2glo} \cdot \left( x^2+1\right) = 2glox^2+2glo $$ |