$$ \begin{aligned}b(b^2-12b+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}b^3-12b^2+b\end{aligned} $$ | |
① | Multiply $ \color{blue}{b} $ by $ \left( b^2-12b+1\right) $ $$ \color{blue}{b} \cdot \left( b^2-12b+1\right) = b^3-12b^2+b $$ |