Answer
$$9a^3b^4(3a^3-5b)=27a^6b^4-45a^3b^5$$
Explanation
| $$ \begin{aligned}9a^3b^4(3a^3-5b)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}27a^6b^4-45a^3b^5\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{9a^3b^4} $ by $ \left( 3a^3-5b\right) $ $$ \color{blue}{9a^3b^4} \cdot \left( 3a^3-5b\right) = 27a^6b^4-45a^3b^5 $$ |
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