Answer
$$7c(c^3-2c^2+5)=7c^4-14c^3+35c$$
Explanation
| $$ \begin{aligned}7c(c^3-2c^2+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7c^4-14c^3+35c\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{7c} $ by $ \left( c^3-2c^2+5\right) $ $$ \color{blue}{7c} \cdot \left( c^3-2c^2+5\right) = 7c^4-14c^3+35c $$ |
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