Answer
$$7a^2+13-8a^2=-a^2+13$$
Explanation
| $$ \begin{aligned}7a^2+13-8a^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-a^2+13\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{7a^2} +13 \color{blue}{-8a^2} = \color{blue}{-a^2} +13 $$ |
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