Question
Answer
$$7(t-4)+5(t-2)=12t-38$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}7(t-4)+5(t-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7t-28+5t-10 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12t-38\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{7} $ by $ \left( t-4\right) $ $$ \color{blue}{7} \cdot \left( t-4\right) = 7t-28 $$Multiply $ \color{blue}{5} $ by $ \left( t-2\right) $ $$ \color{blue}{5} \cdot \left( t-2\right) = 5t-10 $$ |
| ② | Combine like terms: $$ \color{blue}{7t} \color{red}{-28} + \color{blue}{5t} \color{red}{-10} = \color{blue}{12t} \color{red}{-38} $$ |
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