Answer
$$6x^2(7x^2+3x-2)=42x^4+18x^3-12x^2$$
Explanation
| $$ \begin{aligned}6x^2(7x^2+3x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}42x^4+18x^3-12x^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{6x^2} $ by $ \left( 7x^2+3x-2\right) $ $$ \color{blue}{6x^2} \cdot \left( 7x^2+3x-2\right) = 42x^4+18x^3-12x^2 $$ |
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