Answer
$$6+3\cdot(7+6q)+10q=28q+27$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6+3\cdot(7+6q)+10q& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6+21+18q+10q \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}18q+27+10q \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}28q+27\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( 7+6q\right) $ $$ \color{blue}{3} \cdot \left( 7+6q\right) = 21+18q $$ |
| ② | Combine like terms: $$ \color{blue}{6} + \color{blue}{21} +18q = 18q+ \color{blue}{27} $$ |
| ③ | Combine like terms: $$ \color{blue}{18q} +27+ \color{blue}{10q} = \color{blue}{28q} +27 $$ |
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