Answer
$$5(6x^4y^2-7x)-3x+11=30x^4y^2-38x+11$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5(6x^4y^2-7x)-3x+11& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}30x^4y^2-35x-3x+11 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}30x^4y^2-38x+11\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{5} $ by $ \left( 6x^4y^2-7x\right) $ $$ \color{blue}{5} \cdot \left( 6x^4y^2-7x\right) = 30x^4y^2-35x $$ |
| ② | Combine like terms: $$ 30x^4y^2 \color{blue}{-35x} \color{blue}{-3x} +11 = 30x^4y^2 \color{blue}{-38x} +11 $$ |
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