$$ \begin{aligned}4x(3x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12x^2-8x\end{aligned} $$ | |
① | Multiply $ \color{blue}{4x} $ by $ \left( 3x-2\right) $ $$ \color{blue}{4x} \cdot \left( 3x-2\right) = 12x^2-8x $$ |