$$ \begin{aligned}4x^2(x+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^3+16x^2\end{aligned} $$ | |
① | Multiply $ \color{blue}{4x^2} $ by $ \left( x+4\right) $ $$ \color{blue}{4x^2} \cdot \left( x+4\right) = 4x^3+16x^2 $$ |