Answer
$$4(x^2+x)=4x^2+4x$$
Explanation
| $$ \begin{aligned}4(x^2+x)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2+4x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4} $ by $ \left( x^2+x\right) $ $$ \color{blue}{4} \cdot \left( x^2+x\right) = 4x^2+4x $$ |
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