Answer
$$4(t-2)-3(t-3)=t+1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4(t-2)-3(t-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4t-8-(3t-9) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4t-8-3t+9 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}t+1\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4} $ by $ \left( t-2\right) $ $$ \color{blue}{4} \cdot \left( t-2\right) = 4t-8 $$Multiply $ \color{blue}{3} $ by $ \left( t-3\right) $ $$ \color{blue}{3} \cdot \left( t-3\right) = 3t-9 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 3t-9 \right) = -3t+9 $$ |
| ③ | Combine like terms: $$ \color{blue}{4t} \color{red}{-8} \color{blue}{-3t} + \color{red}{9} = \color{blue}{t} + \color{red}{1} $$ |
This page was created using
Simplify polynomials calculator