Answer
$$3y(y^2-2y)=3y^3-6y^2$$
Explanation
| $$ \begin{aligned}3y(y^2-2y)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3y^3-6y^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3y} $ by $ \left( y^2-2y\right) $ $$ \color{blue}{3y} \cdot \left( y^2-2y\right) = 3y^3-6y^2 $$ |
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