Answer
$$3xy^2(2x+3y)=6x^2y^2+9xy^3$$
Explanation
| $$ \begin{aligned}3xy^2(2x+3y)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2y^2+9xy^3\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3xy^2} $ by $ \left( 2x+3y\right) $ $$ \color{blue}{3xy^2} \cdot \left( 2x+3y\right) = 6x^2y^2+9xy^3 $$ |
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